Given A(2|1|-7), B(5|5|5) Distance between A and B : ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ d(A,B) = 13
It's calculated by the formula of Pythagoras.
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d = √( (x1 - x2)2 + (y1 - y2)2 + (z1 - z2)2)
Given P(2|0|3) −> ⎧ 1 ⎫ ⎧ 1 ⎫ g : x = ⎪ 1 ⎪ + s·⎪ 0 ⎪ ⎩ 0 ⎭ ⎩-2 ⎭ Distance between P and g: ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ d(P,g) = 2,4494897
Take the plane E in normal form with the point P as position vector and the direction of the line g as normal vector. Determine the point of intersection S between this plane and the line g. The distance between S and P is the distance between the point and the line.
Given P(0|0|0) E : x + y = 1 Distance between P and E : ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ d(P,E) = -0,70710678
Intersect the plane by the perpendicular from the point to the plane and determine the distance between the point of intersection and the given point.
See Intersection of Plane and Line