MatheAss: News
MatheAss is also revised from time to time between updates, mostly based on user instructions. With version 9.0 a new version is now available with many new functions.
What's new in MatheAss 9.0?
The following program parts have been added:
 Prime tuples
 In an interval [a,b], all prime twins (p,p+2), prime cousins (p,p+4), sexy primes (p,p+6) and prime triplets are determined.
 Calculating percentages
 The base value G, the percentage value W, the percentage p or p%, the growth factor q and the final value E are calculated if two independent values ??are entered.
 Special straight lines in a triangle
 The program determines the equations of the perpendiculars, the bisectors of the sides, the bisectors of the angles and the heights of a triangle. In addition, the centers and radii of the circumference, the inscribed circle and the three excircles.
 Mappings of Polygons

Displacement, straight line mirroring, point mirroring, rotation, centric stretching and shear can be applied to an ngon.
The input has been made clearer and the construction lines can be drawn in the diagram.  Factoring polynomials
 The program calculates the rational zeros and the linear factorization of a polynomial.
 Transforming polynomials
 A polynomial p(x) can be shifted or stretched in the xdirection and ydirection.
 Polynomial functions
 The program carries out the curve discussion for polynomial function. This means that the derivatives and the antiderivative are determined, the function is examined for rational zeros, for extremes, for inflection points and for symmetry.
 Rational functions
 The program carries out the curve discussion for a rational function. That is, the derivatives, the definition gaps and the continuous continuation are determined. The function is examined for zeros, extrema, points of inflection: and the behavior for  x  → ∞.
 Statistics
 In the statistics section, the histogram was supplemented by a box plot.
 Logistic regression
 The program determines a curve fit for a series of measurements to the logistic function
with the parameters a_{1} = ƒ(0)·S , a_{2} = ƒ(0) , a_{3} = S  ƒ(0) , und a_{4} = k·S and the saturation limit S .  Data series from Johns Hopkins University (JHU) on the corona pandemic are attached as CSV files.
Prime triplets between 1 and 200 (357) (5711) [71113] (111317) [131719] (171923) [374143] (414347) [677173] [97101103] (101103107) [103107109] (107109113) (191193197) [193197199] 15 Prime triplets 7 of the form (pp+2p+6) and 7 of the form [pp+4p+6]
Percentage value W = 120 Growth factor q = 95% = 0,95 = 19/20 Results: Basic value G = 2400 Percentage p% = 5% = 0,05 = 1/20 Final value E = 2280
Given: ====== Edges: A(10) B(51) C(36) Results: ======== Vertices: a : 5·x + 2·y = 27 b : 3·x  y = 3 c : x  4·y = 1 Incircle: Mi(3,1191,962) ri = 1,390 Excircles: Ma(7,6266,136) ra = 4,346 Mb(4,3565,784) rb = 6,910 Mc(3,2482,427) rc = 2,900
Counter image A(11), B(51), C(55), D(37), E(15), 1. Translation: dx=2, dy=1 ☑ A(32), B(72), C(76), D(58), E(36), 2. Rotation: Z(21), α=60° ☑ A(5,09810,36603), B(7,09813,8301), C(10,5621,8301), D(11,2940,90192), E(8,56221,634),
p(x) = x^{5}  9·x^{4}  82/9·x^{3} + 82·x^{2} + x  9 = (1/9)·(9·x^{5}  81·x^{4}  82·x^{3} + 738·x^{2} + 9·x  81) = (1/9)·(3·x  1)·(3·x + 1)·(x  9)·(x  3)·(x + 3) Rational Zeros: 1/3, 1/3, 9, 3, 3
ƒ(x) =  1/4·x^{4} + 2·x^{3}  16·x + 21 Shifted by dx = 2 , dy = 0 ƒ(x + 2) =  1/4·x^{4} + 6·x^{2} + 1
Function : ¯¯¯¯¯¯¯¯ ƒ(x) = 3·x^{4}  82/3·x^{2} + 3 = 1/3·(9·x^{4}  82·x^{2} + 9) = 1/3·(3·x  1)·(3·x + 1)·(x  3)·(x + 3) Derivations : ¯¯¯¯¯¯¯¯¯¯ ƒ'(x) = 12·x^{3}  164/3·x ƒ"(x) = 36·x^{2}  164/3 ƒ'"(x) = 72·x Antiderivative: ¯¯¯¯¯¯¯¯¯¯¯¯ ƒ(x) = 3/5·x^{5}  82/9·x^{3} + 3·x + c …
Function : ¯¯¯¯¯¯¯¯ 3·x^{3} + x^{2}  4 (x  1)·(3·x^{2} + 4·x + 4) ƒ(x) = —————— = ——————————— 4·x^{2}  16 4·(x  2)·(x + 2) Definition gaps : ¯¯¯¯¯¯¯¯¯¯¯¯¯ x = 2 Pol mit Vorzeichenwechsel x =2 Pol mit Vorzeichenwechsel Derivations : ¯¯¯¯¯¯¯¯¯¯ 3·(x^{4}  12·x^{2}) 3·(x^{2}·(x^{2}  12)) ƒ'(x) = ———————— = ————————— 4·(x^{4}  8·x^{2} + 16) 4·(x  2)^{2}·(x + 2)^{2} 6·(x^{3} + 12·x) 6·(x·(x^{2} + 12)) ƒ"(x) = ——————————— = ———————— x^{6}  12·x^{4} + 48·x^{2}  64 (x  2)^{3}·(x + 2)^{3} …
Data from: "\Hopfenwachstum.csv" Saturation limit: 6 Dark figure: 1 ƒ(t) = 4,0189 / (0,66981 + 5,3302*e^(0,35622*t) ) Inflection point W(5,8226/3) Maximum growth rate f'(xw) = 0,53433 8 Values Coeff.of determin. = 0,99383916 Correlation coeff. = 0,99691482 Standard deviation = 0,16172584
How much costs MatheAss 9.0?
29 € for the private license
79 € for the school license
360 € for the extended school license, with which the serial number may be passed on to the pupils.
How much is the update?
10 € for owners of a private license
30 € for owners of a school license
90 € for owners of an extended school license
How can I pay?
Here by PayPal :